A decoder has one output for each combination of its inputs, and exactly one output is high at a time. With every input and its inverse available, each output is a gate that reads one signal of each pair.
Hint
Each output is high for one combination only, so it is a NOR gate of the two signals that are low in that combination. The inverters of A1 and A0 are drawn: feed each NOR gate an input or its inverse from each pair.
Solution
This is the game's reference drawing for the puzzle. It meets the goal and passes the design rules. Other drawings can pass as well.
Top View of the solved die, captured from the game. Paths that carry a high level at the moment shown are lit. The Side View below cuts through the row between the dashed lines.The whole game window in Isometric View. The scope on the right compares each output with its target band, and the message above it confirms that the drawing passes.The solution on the grid. Squares are numbered from the top left corner, so you can count them. The dashed outline marks the squares you draw, change, or erase; the rest is drawn when the puzzle opens.
Legend
Metal323 squares
Polysilicon104 squares
Contact78 squares
N active46 squares
P active92 squares
N well170 squares
Metal 2201 squares
Via40 squares
Input padA0, A1
Output padY0, Y1, Y2, Y3
Supply padVDD
Ground padGND
Squares you draw, change, or erase400 squares
About the drawing
The drawing uses 572 of the die's 884 squares.
Part of the drawing is in place when the puzzle opens. To finish it, paint 291 empty squares and change 109 drawn squares.
It forms 20 transistors: 10 N transistors and 10 P transistors. Each one is a place where polysilicon crosses active silicon.
78 contacts join metal to the polysilicon or active silicon under it.
40 vias join metal 2 to the metal under it.
The drawing when the puzzle opens. The dashed outline marks the squares the solution changes.