A flip-flop takes D on every clock edge. Feeding its own Q back to D makes it keep its value, so a multiplexer in front of D chooses between keeping and loading.
Hint
Feed D from a pair of switches that pass A while EN is high and Q while EN is low. The switches need EN in both senses, so add an inverter for EN.
Solution
This is the game's reference drawing for the puzzle. It meets the goal and passes the design rules. Other drawings can pass as well.
Top View of the solved die, captured from the game. Paths that carry a high level at the moment shown are lit. The Side View below cuts through the row between the dashed lines.The whole game window in Isometric View. The scope on the right compares each output with its target band, and the message above it confirms that the drawing passes.The solution on the grid. Squares are numbered from the top left corner, so you can count them. The dashed outline marks the squares you draw, change, or erase; the rest is drawn when the puzzle opens.
Legend
Metal306 squares
Polysilicon53 squares
Contact35 squares
N active19 squares
P active19 squares
N well81 squares
Metal 2332 squares
Via49 squares
Input padCLK, CLKN, A, EN
Output padQ
Supply padVDD, VDD
Ground padGND, GND
Squares you draw, change, or erase320 squares
About the drawing
The drawing uses 547 of the die's 870 squares.
Part of the drawing is in place when the puzzle opens. To finish it, paint 278 empty squares and change 42 drawn squares.
It forms 14 transistors: 7 N transistors and 7 P transistors. Each one is a place where polysilicon crosses active silicon.
35 contacts join metal to the polysilicon or active silicon under it.
49 vias join metal 2 to the metal under it.
The drawing when the puzzle opens. The dashed outline marks the squares the solution changes.