Width in series
Transistors in series share one path, and the current of the pair is limited by both. To match one transistor two squares wide, two in series need four squares each.
Puzzle 26 of 100
Y now drives a large load. Widen the transistors so that both edges are at least as fast as the target.
Transistors in series share one path, and the current of the pair is limited by both. To match one transistor two squares wide, two in series need four squares each.
Two N transistors in series pass about half the current of one, so each needs twice the width of a single pull-down. Each P transistor pulls Y up on its own.
This is the game's reference drawing for the puzzle. It meets the goal and passes the design rules. Other drawings can pass as well.

