A reset that acts through D takes effect at the next rising edge of the clock. It gives the flip-flop a known level, so Q can be judged against a target from the first edge.
Hint
Replace the inverter that feeds D with a NOR gate of Q and R. While R is high the NOR gate holds D low, so the next rising edge stores a low.
Solution
This is the game's reference drawing for the puzzle. It meets the goal and passes the design rules. Other drawings can pass as well.
Top View of the solved die, captured from the game. Paths that carry a high level at the moment shown are lit. The Side View below cuts through the row between the dashed lines.The whole game window in Isometric View. The scope on the right compares each output with its target band, and the message above it confirms that the drawing passes.The solution on the grid. Squares are numbered from the top left corner, so you can count them. The dashed outline marks the squares you draw, change, or erase; the rest is drawn when the puzzle opens.
Legend
Metal206 squares
Polysilicon142 squares
Contact45 squares
N active35 squares
P active70 squares
N well160 squares
Metal 277 squares
Via11 squares
Input padCLK, R
Output padQ
Supply padVDD
Ground padGND
Squares you draw, change, or erase47 squares
About the drawing
The drawing uses 457 of the die's 560 squares.
Part of the drawing is in place when the puzzle opens. To finish it, paint 14 empty squares, change 29 drawn squares, and erase 4 squares.
It forms 18 transistors: 9 N transistors and 9 P transistors. Each one is a place where polysilicon crosses active silicon.
45 contacts join metal to the polysilicon or active silicon under it.
11 vias join metal 2 to the metal under it.
The drawing when the puzzle opens. The dashed outline marks the squares the solution changes.