Next state logic can lead a state back to itself. Once the machine reaches such a state it stays there, as a counter that stops at its last value.
Hint
Q1 goes high once either bit is high, so D1 is a NAND gate of QN1 and QN0. Q0 goes low only from the count 1, so D0 is a NAND gate of Q0 and QN1.
Solution
This is the game's reference drawing for the puzzle. It meets the goal and passes the design rules. Other drawings can pass as well.
Top View of the solved die, captured from the game. Paths that carry a high level at the moment shown are lit. The Side View below cuts through the row between the dashed lines.The whole game window in Isometric View. The scope on the right compares each output with its target band, and the message above it confirms that the drawing passes.The solution on the grid. Squares are numbered from the top left corner, so you can count them. The dashed outline marks the squares you draw, change, or erase; the rest is drawn when the puzzle opens.
Legend
Metal295 squares
Polysilicon88 squares
Contact54 squares
N active32 squares
P active32 squares
N well132 squares
Metal 2349 squares
Via63 squares
Input padCLK, CLKN
Output padQ0, Q1
Supply padVDD, VDD
Ground padGND, GND
Squares you draw, change, or erase222 squares
About the drawing
The drawing uses 633 of the die's 1015 squares.
Part of the drawing is in place when the puzzle opens. To finish it, paint 205 empty squares and change 17 drawn squares.
It forms 24 transistors: 12 N transistors and 12 P transistors. Each one is a place where polysilicon crosses active silicon.
54 contacts join metal to the polysilicon or active silicon under it.
63 vias join metal 2 to the metal under it.
The drawing when the puzzle opens. The dashed outline marks the squares the solution changes.