A longer channel passes less current, and a larger load needs more charge, so either one slows a single stage. Changing one transistor or one load moves the period by less than a whole pair of stages.
Hint
Two more stages would overshoot the period. Slow one stage a little instead: make the channel of one transistor in the ring two squares long, or give a ring node more load, such as a wider output inverter.
Solution
This is the game's reference drawing for the puzzle. It meets the goal and passes the design rules. Other drawings can pass as well.
Top View of the solved die, captured from the game. Paths that carry a high level at the moment shown are lit. The Side View below cuts through the row between the dashed lines.The whole game window in Isometric View. The scope on the right compares each output with its target band, and the message above it confirms that the drawing passes.The solution on the grid. Squares are numbered from the top left corner, so you can count them. The dashed outline marks the squares you draw, change, or erase; the rest is drawn when the puzzle opens.
Legend
Metal145 squares
Polysilicon72 squares
Contact33 squares
N active15 squares
P active30 squares
N well92 squares
Input padEN
Output padY
Supply padVDD
Ground padGND
Squares you draw, change, or erase95 squares
About the drawing
The drawing uses 253 of the die's 420 squares.
Part of the drawing is in place when the puzzle opens. To finish it, paint 20 empty squares, change 65 drawn squares, and erase 10 squares.
It forms 10 transistors: 5 N transistors and 5 P transistors. Each one is a place where polysilicon crosses active silicon.
33 contacts join metal to the polysilicon or active silicon under it.
The drawing when the puzzle opens. The dashed outline marks the squares the solution changes.